8k^2+4k-4=0

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Solution for 8k^2+4k-4=0 equation: 



8k^2+4k-4=0

a = 8; b = 4; c = -4;
Δ = b2-4ac
Δ = 42-4·8·(-4)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$


$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-12}{2*8}=\frac{-16}{16}
=-1
$


$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+12}{2*8}=\frac{8}{16}
=1/2
$

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